3.7.6 \(\int x^3 (a+b x^4) \, dx\) [606]

Optimal. Leaf size=17 \[ \frac {a x^4}{4}+\frac {b x^8}{8} \]

[Out]

1/4*a*x^4+1/8*b*x^8

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Rubi [A]
time = 0.00, antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {14} \begin {gather*} \frac {a x^4}{4}+\frac {b x^8}{8} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^3*(a + b*x^4),x]

[Out]

(a*x^4)/4 + (b*x^8)/8

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
 &&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rubi steps

\begin {align*} \int x^3 \left (a+b x^4\right ) \, dx &=\int \left (a x^3+b x^7\right ) \, dx\\ &=\frac {a x^4}{4}+\frac {b x^8}{8}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 17, normalized size = 1.00 \begin {gather*} \frac {a x^4}{4}+\frac {b x^8}{8} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^3*(a + b*x^4),x]

[Out]

(a*x^4)/4 + (b*x^8)/8

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Maple [A]
time = 0.04, size = 15, normalized size = 0.88

method result size
gosper \(\frac {1}{4} a \,x^{4}+\frac {1}{8} b \,x^{8}\) \(14\)
norman \(\frac {1}{4} a \,x^{4}+\frac {1}{8} b \,x^{8}\) \(14\)
default \(\frac {\left (b \,x^{4}+a \right )^{2}}{8 b}\) \(15\)
risch \(\frac {b \,x^{8}}{8}+\frac {a \,x^{4}}{4}+\frac {a^{2}}{8 b}\) \(22\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(b*x^4+a),x,method=_RETURNVERBOSE)

[Out]

1/8*(b*x^4+a)^2/b

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Maxima [A]
time = 0.30, size = 14, normalized size = 0.82 \begin {gather*} \frac {{\left (b x^{4} + a\right )}^{2}}{8 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x^4+a),x, algorithm="maxima")

[Out]

1/8*(b*x^4 + a)^2/b

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Fricas [A]
time = 0.36, size = 13, normalized size = 0.76 \begin {gather*} \frac {1}{8} \, b x^{8} + \frac {1}{4} \, a x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x^4+a),x, algorithm="fricas")

[Out]

1/8*b*x^8 + 1/4*a*x^4

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Sympy [A]
time = 0.01, size = 12, normalized size = 0.71 \begin {gather*} \frac {a x^{4}}{4} + \frac {b x^{8}}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(b*x**4+a),x)

[Out]

a*x**4/4 + b*x**8/8

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Giac [A]
time = 2.03, size = 13, normalized size = 0.76 \begin {gather*} \frac {1}{8} \, b x^{8} + \frac {1}{4} \, a x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x^4+a),x, algorithm="giac")

[Out]

1/8*b*x^8 + 1/4*a*x^4

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Mupad [B]
time = 0.02, size = 13, normalized size = 0.76 \begin {gather*} \frac {b\,x^8}{8}+\frac {a\,x^4}{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a + b*x^4),x)

[Out]

(a*x^4)/4 + (b*x^8)/8

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